X^2+8x-98=0

Solution for X^2+8x-98=0 equation:

X^2+8X-98=0

a = 1; b = 8; c = -98;
Δ = b2-4ac
Δ = 82-4·1·(-98)
Δ = 456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{456}=\sqrt{4*114}=\sqrt{4}*\sqrt{114}=2\sqrt{114}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{114}}{2*1}=\frac{-8-2\sqrt{114}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{114}}{2*1}=\frac{-8+2\sqrt{114}}{2}
$